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</o:shapelayout></xml><![endif]--></head><body lang=FR link="#0563C1" vlink="#954F72"><div class=WordSection1><p class=MsoNormal>Hello,<o:p></o:p></p><p class=MsoNormal><o:p> </o:p></p><p class=MsoNormal><span lang=EN-GB>I can’t figure out how the “timeout_socket” should be configured.<o:p></o:p></span></p><p class=MsoNormal><span lang=EN-GB>I try with the default parameter in the doc: xmlrpc:http://127.0.0.1:8000/RPC2<o:p></o:p></span></p><p class=MsoNormal><span lang=EN-GB>I launch RTPProxy like that: -n tcp:127.0.0.1:8000<o:p></o:p></span></p><p class=MsoNormal><span lang=EN-GB>RTPProxy socket is setup like: "rtpproxy_sock", "udp:127.0.0.1:7722".<o:p></o:p></span></p><p class=MsoNormal><span lang=EN-GB><o:p> </o:p></span></p><p class=MsoNormal><span lang=EN-GB>It looks like there is no communication on the port 8000. The goal is to setup a timeout in case of asymmetric RTP.<o:p></o:p></span></p><p class=MsoNormal><span lang=EN-GB><o:p> </o:p></span></p><p class=MsoNormal><span lang=EN-GB>Many help would be appreciate. Thank you!<o:p></o:p></span></p><p class=MsoNormal><span lang=EN-GB><o:p> </o:p></span></p><p class=MsoNormal><span lang=EN-GB>Regards,<o:p></o:p></span></p><p class=MsoNormal><span lang=EN-GB><o:p> </o:p></span></p><p class=MsoNormal><span lang=EN-GB>Igor.<o:p></o:p></span></p></div></body></html>